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力扣:修改后的最大二进制字符串
阅读量:403 次
发布时间:2019-03-05

本文共 1471 字,大约阅读时间需要 4 分钟。

??????????????????????????????????????1??00?????10????2??10?????01???????????????????????????1?????????????

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    import java.util.ArrayList;import java.util.List;public class Solution {    public String maximumBinaryString(String binary) {        char[] chars = binary.toCharArray();        int length = chars.length;        List
    zeroPositions = new ArrayList<>(); // ????0??? for (int i = 0; i < length; i++) { if (chars[i] == '0') { zeroPositions.add(i); } } // ?????????0 for (int i = zeroPositions.size() - 2; i >= 0; i--) { int current = zeroPositions.get(i); int next = zeroPositions.get(i + 1); if (next == current + 1) { // ???10 chars[current] = '1'; chars[next] = '0'; // ??zeroPositions???current?next???????? zeroPositions.remove(i); zeroPositions.remove(i); zeroPositions.add(next); } } return new String(chars); }}

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